comp << l['Address'] unless l['Address'].empty?
comp << l['City'] unless l['City'].empty?
comp << l['State'] unless l['State'].empty?
comp << l['Zip'] unless l['Zip'].empty?
comp << l['Country'] unless l['Country'].empty?
but I made some changes so that all of the keys would now be lowercase and turned into symbols. Basically I wanted the output to look like this:
comp << l[:address] unless l[:address].empty?
comp << l[:city] unless l[:city].empty?
comp << l[:state] unless l[:state].empty?
comp << l[:zip] unless l[:zip].empty?
comp << l[:country] unless l[:country].empty?
With a little help from an ex coworker's blog, I was able to achieve this using the following regular expression:
M-x replace-regexp
l\['\([A-Z]\)\([^']*\)'\]
l[:\,(downcase \1)\2]
Note that the '\,' (backslash-comma) combination escapes the lisp command that is part of the replacement text.
I never ceased to be amazed by the power of emacs. I'm still decades away from being able to develop a webservice in lisp. :)
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